secAcotB-secA-2cotB+2=0
secA(cotB-1) + 2(cotB-1) = 0
(secA+2)(cotB-1) = 0
Now it should be clear what the angles are.
Find the acute angles A and B satisfying secAcotB-secA-2cotB+2=0
Ans : secAcotB-secA-2cotB+2=0
2cotB-secAcotB+secA=2
2 answers
Not got the answer