Asked by Aarti

Find the acute angles A and B satisfying secAcotB-secA-2cotB+2=0

Ans : secAcotB-secA-2cotB+2=0
2cotB-secAcotB+secA=2

10 years ago

Answered by Steve

secAcotB-secA-2cotB+2=0
secA(cotB-1) + 2(cotB-1) = 0
(secA+2)(cotB-1) = 0

Now it should be clear what the angles are.

10 years ago

Answered by anu

Not got the answer

8 years ago

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