Asked by Kar
Sheila has 7y craft sticks. Mark has 4y fewer craft sticks then Sheila and y craft sticks more than Linda. Then Sheila gave 2y craft sticks to Mark and Linda. How many craft sticks in terms of y did Mark and Linda have in the end?
If mark had 6 more craft sticks than Linda at first how many many craft sticks would mark and Linda have in the end?
If mark had 6 more craft sticks than Linda at first how many many craft sticks would mark and Linda have in the end?
Answers
Answered by
Henry
1. Sheila: 7y Craft sticks.
Mark: 7y-4y = 3y
Linda: 3y-y = 2y
In the end:
Sheila: 7y-2y-2y = 3y
Mark: 3y + 2y = 5y
Linda: 2y + 2y = 4y
2. Mark: 3y
Linda: 3y - 6
Mark: 7y-4y = 3y
Linda: 3y-y = 2y
In the end:
Sheila: 7y-2y-2y = 3y
Mark: 3y + 2y = 5y
Linda: 2y + 2y = 4y
2. Mark: 3y
Linda: 3y - 6
Answered by
Henry
Oops! Posted pre-maturely.
2. Mark: 3y
Linda: 3y - 6
In the end:
Mark: 3y + 2y = 5y
Linda: (3y-6) + 2y = 5y - 6
2. Mark: 3y
Linda: 3y - 6
In the end:
Mark: 3y + 2y = 5y
Linda: (3y-6) + 2y = 5y - 6
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