Question
a piece of ribbon is cut into two shorter pieces in the ratio 2.8 : 1.25
The difference in the length of the shorter pieces is 80.6 cm.
What is the length of the original piece?
The difference in the length of the shorter pieces is 80.6 cm.
What is the length of the original piece?
Answers
Reiny
reduce the ratio:
2.8 : 1.25
= 280 : 125
= 56 : 25
let the ratio of the ribbons be
56x : 25x
"The difference in the length of the shorter pieces is 80.6 cm. "
This makes no sense, I will assume you meant that the difference in the length of the two pieces is 80.6
56x - 25x = 80.6
x = 80.6/31 = 806/310 = 13/5 = 2.6
so the original piece = 56x + 25x = 81x
81x = 81(2.6) = 210.6
The original was 210.6 cm
check:
the pieces are 56(2.6) and 25(2.6) cm or
145.6 cm and 65 cm
sum = 145.6+65 = 210.6 , check!
ratio of 145.6 : 65
= 1456 : 650 ----> divide each by 520
= 2.8 : 1.25 , check!
=
2.8 : 1.25
= 280 : 125
= 56 : 25
let the ratio of the ribbons be
56x : 25x
"The difference in the length of the shorter pieces is 80.6 cm. "
This makes no sense, I will assume you meant that the difference in the length of the two pieces is 80.6
56x - 25x = 80.6
x = 80.6/31 = 806/310 = 13/5 = 2.6
so the original piece = 56x + 25x = 81x
81x = 81(2.6) = 210.6
The original was 210.6 cm
check:
the pieces are 56(2.6) and 25(2.6) cm or
145.6 cm and 65 cm
sum = 145.6+65 = 210.6 , check!
ratio of 145.6 : 65
= 1456 : 650 ----> divide each by 520
= 2.8 : 1.25 , check!
=
Hahaha
Coolllllllk brooomim tryna cheat on this test thanks
mtn name'
210.6 yw