yes, (3a^5)^2 = 9a^10
6x^2 * 12x^3 = 72x^5
Why did you assume x=5?
How do you solve the following problems:
What is the area of a square with the length of a side equaling 3a^5?
I got (3a^5)(3a^5)=9a^10 is that correct??
What is the area of the rectangle with the width of 6x^2 and the length of 12x^3?
I got 6*5^2=900; 12*5^3=216,000 for a total of 216,900 is that correct?
If they are wrong can you show me how to do them? THANKS
3 answers
oh sorry on the worksheet it said to evaluate each monomial for x=5, y=-1, and z=4
Steve: was my answer correct? 216,900?