draw the vector diagram, mg donward, horizontal force=kqq/.026^2
tan 20= mg/(kqq/.026^2)
you know mass m, g, k, solve for q.
There are two pit balls equally charged and each with a mass of 1.5g. While one ball is suspended by a thread, the other is brought close to it and state of equilibrium is reached. In that situation,the two balls are separated by 2.6cm and the thread attached to the suspended ball makes an angle of 20 degrees with the vertical. Calculate the charge on each the pith balls.
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