Asked by lucy
a car rolls down a ramp 4m long that has angle of incline equal to 37 degrees. If the car starts from rest, what will be its velocity at the bottom of the ramp?
Answers
Answered by
Henry
h = 4*sin37 = 2.41 m.
V^2 = Vo^2 + 2g*h
Vo = 0
g = 9.8 m/s^2
h = 2.41 m
Solve for V.
V^2 = Vo^2 + 2g*h
Vo = 0
g = 9.8 m/s^2
h = 2.41 m
Solve for V.
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