a car rolls down a ramp 4m long that has angle of incline equal to 37 degrees. If the car starts from rest, what will be its velocity at the bottom of the ramp?

Answer 1

h = 4*sin37 = 2.41 m.

V^2 = Vo^2 + 2g*h

Vo = 0
g = 9.8 m/s^2
h = 2.41 m
Solve for V.