Question
A 3kg mass is sliding across a horizontal surface at a constant speed while being pulled by rope with tension 20N held at a 53 degree angle above the horizontal. The force of friction is most nearly
A. 30N
B. 12N
C. 16N
D. 20N
E. 1N
A. 30N
B. 12N
C. 16N
D. 20N
E. 1N
Answers
Henry
Tx = 20*Cos53 = 12 N. = Hor. component
of tension.
Tx-Fk = M*a
12-Fk = M*0 = 0
Fk = 12 N.
of tension.
Tx-Fk = M*a
12-Fk = M*0 = 0
Fk = 12 N.