Tx = 20*Cos53 = 12 N. = Hor. component
of tension.
Tx-Fk = M*a
12-Fk = M*0 = 0
Fk = 12 N.
A 3kg mass is sliding across a horizontal surface at a constant speed while being pulled by rope with tension 20N held at a 53 degree angle above the horizontal. The force of friction is most nearly
A. 30N
B. 12N
C. 16N
D. 20N
E. 1N
1 answer
1 answer