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A 3kg mass is sliding across a horizontal surface at a constant speed while being pulled by rope with tension 20N held at a 53 degree angle above the horizontal. The force of friction is most nearly

A. 30N
B. 12N
C. 16N
D. 20N
E. 1N
10 years ago

Answers

Henry
Tx = 20*Cos53 = 12 N. = Hor. component
of tension.

Tx-Fk = M*a
12-Fk = M*0 = 0
Fk = 12 N.
10 years ago

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