Asked by Julius
A 10 foot long ladder is leaning against a vertical wall with the top of the ladder 8ft from the ground. What is the slope of the ladder? How far is the foot of the ladder from the wall? Can a 6 foot tall man walk under the ladder 1 foot from the wall? Justify your answer.
Answers
Answered by
Reiny
looks like plain ol' Pythagoras
base^2 + 8^2 = 10^2
bse^2 = 100-64 = 36
base = √36 = 6
slope = rise/run = height/base = 8/6 = 4/3
Make a sketch of the situation
Place the 6-ft man on the base 3 ft from the base.
Is he below the ladder or did his head hit the ladder?
Prove your conclusion with calculations.
base^2 + 8^2 = 10^2
bse^2 = 100-64 = 36
base = √36 = 6
slope = rise/run = height/base = 8/6 = 4/3
Make a sketch of the situation
Place the 6-ft man on the base 3 ft from the base.
Is he below the ladder or did his head hit the ladder?
Prove your conclusion with calculations.
Answered by
Anonymous
a soccer game is being televised by a certain tv station. a camera is situated 10 meters away from the longer side of the soccer field and 7 meters from the middle part.
Answered by
MacDonald
answer
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