John was visiting three cities that lie on a coordinate grid at (-4, 5), (4, 5), and (-3, -4). If he visited all the cities and ended up where he started, what is the distance he traveled? Round your answer to the nearest tenth. (like 3.2 or 5.7)
4 answers
did he have to follow the grid, or could he take diagonal shortcuts?
no
mmmh, diagonals in a triangle ?
Label your given points A, B, and C in the corresponding order.
Clearly AB is a horizontal line, thus AB = 8
AC = √(1^2 + 9^2) = √82
BC = √(7^2 + 9^2) = √130
perimeter = 8 + √82 + √130 = appr 28.5
Label your given points A, B, and C in the corresponding order.
Clearly AB is a horizontal line, thus AB = 8
AC = √(1^2 + 9^2) = √82
BC = √(7^2 + 9^2) = √130
perimeter = 8 + √82 + √130 = appr 28.5
billy: "no" to which question?
If you mean "no, he does not have to follow the grid (that is, travel only horizontally or vertically)," then Reiny's comments (Thanks for stepping up, Reiny) solve the problem
If you mean "no, he cannot travel diagonally" then the distance traveled is the perimeter of an 8x9 rectangle.
If you mean "no, he does not have to follow the grid (that is, travel only horizontally or vertically)," then Reiny's comments (Thanks for stepping up, Reiny) solve the problem
If you mean "no, he cannot travel diagonally" then the distance traveled is the perimeter of an 8x9 rectangle.
1 answer