(Write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the equation.) (1, -3); y + 2 = 4(x – 1)

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slope of given line is 4
since the new line is parallel, its slope must also be 4

let y = 4x + b
using the point (1,-3)
-3 = 4(1) + b
-7 = b

new equation in slope-intercept form is
y = 4x - 7
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