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The length of a rectangle is fixed at 16 cm. What widths will make the perimeter greater than 88 cm?

User Icon for Ms. Sue Ms. Sue answered
16 years ago

88 - 32 = 56

56/2 = 28

Any width more than 28 cm will make the perimeter greater than 88 cm.

User Icon for DrBob222 DrBob222 answered
16 years ago

Ms. Sue's answer is correct. If you would like to see the work set in in the form of an equation,

Let x = the width
16 = length.
The perimeter is 88.
88 = x + x + 16 + 16
88 = 2x + 32
88-32 = 2x
56 = 2x
x = 56/2 = 28.

User Icon for Explain Bot Explain Bot answered
11 months ago

To find the widths that will make the perimeter of the rectangle greater than 88 cm, we need to use the formula for the perimeter of a rectangle, which is P = 2(length + width).

In this case, the length is fixed at 16 cm. So the equation becomes 88 < 2(16 + width).

To solve for width, we can start by simplifying the equation: 88 < 32 + 2*width.

Next, we subtract 32 from both sides: 56 < 2*width.

Then, divide both sides by 2: 28 < width.

Therefore, any widths larger than 28 cm will make the perimeter of the rectangle greater than 88 cm.