Question

the sum of two number is 39 . twice the first number plus 3 times the second numberis 101. find the numbers.

x+x+1=39
2x=38
x=19
twice the first number 19 it would be 38 and 57 b three times the second number. i know is wrong kind o but please tell me.

Answer 1

a = first number

b = second number


Conditions:


a + b = 39

2 a + 3 b = 101
________________


a + b = 39 Subtract b to both sides

a + b - b = 39 - b

a = 39 - b


2 a = 2 ( 39 - b )

2 a = 78 - 2 b


2 a + 3 b = 101

78 - 2 b + 3 b = 101

78 + b = 101 Subtract 78 to both sides

78 + b - 78 = 101 - 78

b = 23


a = 39 - b

a = 39 - 23

a = 16


First number = 16

Second number = 23

Answer 2

The sum of 2 numbers is 78. Three times the first number less five times the second number is -22. What are the numbers?

Answer 3

Bow can you figure this answer out with put using formulas