Asked by Anonymous

A body was found at 6 a.m. outdoors on a day when the temperature was 50oF. The medical examiner found the temperature of the body to be 66oF. What was the approximate time of death? Use Newton's law of cooling, with k = 0.1947.

A. Midnight (12 a.m.)

B. 5 a.m.

C. 2 a.m.

D. 3 a.m.
Answered by Steve
T(t) = To + (50-To)e^-.1947t

I think we can assume that To = 98.6, so

T(t) = 98.6 - 48.6 e^-.1947t

So, just solve for t in T(t) = 66.

That will give the number of hours since death (t=0).
Answered by Anonymous
okay thanks :)
Answered by Anonymous
2 am
Answered by Anonymous
Midnight actually. Just took the test
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