Asked by gh
A square has a length of x inches and a width of 2 inches less than the length. If the dimensions
were doubled, what would be the area of the new square in terms of x?
A.(2x-4)in^2
B.(8x-8)in^2
C.(2x^2-4x)in^2
D.(4x^2-8x)in^2
were doubled, what would be the area of the new square in terms of x?
A.(2x-4)in^2
B.(8x-8)in^2
C.(2x^2-4x)in^2
D.(4x^2-8x)in^2
Answers
Answered by
gh
I think D
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