Asked by assma
Let x1,x2,x3 be random sample of normal(6,4), find P(max{x1,x2,x3}>8)
Answers
Answered by
MathMate
Look up normal probability table for X~N(6,4) for P(X<8)=0.69 (approx.), so
P(X>8)=0.31.
Since we have random samples which we assume to be independent, we can use binomial probability distribution to calculate P(max{x1,x2,x3}>8).
Alternatively, we can calculate
P(all X<8)=0.69³, then
P(at least one >8)=1-0.69³.
P(X>8)=0.31.
Since we have random samples which we assume to be independent, we can use binomial probability distribution to calculate P(max{x1,x2,x3}>8).
Alternatively, we can calculate
P(all X<8)=0.69³, then
P(at least one >8)=1-0.69³.
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