Asked by Anonymous
Find the value of c which satisfies Mean Value Theorem for the function f(x)=sin(x) on the closed interval (-3ð/2,3ð/2).
Answers
Answered by
Damon
y = sin x
y' = cos x
I guess that is -3 pi/2 to + 3 pi/2
sin 3 pi/2 = -1
sin -3 pi/2 = 1
-1 - 1 = -2
-1/(3 pi) = -.1061
cos^-1 -.1061 = 96.1 degrees
= 1.677 radians
cos is odd function so also -1.677 radians
y' = cos x
I guess that is -3 pi/2 to + 3 pi/2
sin 3 pi/2 = -1
sin -3 pi/2 = 1
-1 - 1 = -2
-1/(3 pi) = -.1061
cos^-1 -.1061 = 96.1 degrees
= 1.677 radians
cos is odd function so also -1.677 radians
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