Asked by jessica
                what is the velocity (in ft/s) of a sandbag 2.75 s after it is released from a hot-air balloon that is stationary in the air?
            
            
        Answers
                    Answered by
            Henry
            
    V = Vo + g*t
Vo = 0
g = 9.8
t = 2.75 s.
Solve for V.
    
Vo = 0
g = 9.8
t = 2.75 s.
Solve for V.
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