Asked by Maths Learner
math question from applications of the derivatives.
maths formula:
V = 4/3(pi)r^3
dV = 4(pi)(3r^2)
= 4(pi)r^2
But I don't understanding that how to get (3r^2) ?
maths formula:
V = 4/3(pi)r^3
dV = 4(pi)(3r^2)
= 4(pi)r^2
But I don't understanding that how to get (3r^2) ?
Answers
Answered by
Steve
d/dr (r^3) = 3r^2
It's just the normal power formula
So,
dV/dr = (4/3)pi (3r^2)
dV = 4pi r^2 dr
Don't lose track of the dr when doing related rates
It's just the normal power formula
So,
dV/dr = (4/3)pi (3r^2)
dV = 4pi r^2 dr
Don't lose track of the dr when doing related rates
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