Question
determine the molarity of each of the ions present in the following aqueous salt solutions (assume 100% ionization)
1.25 M CuBr2
how many grams of each ion would be present in 100mL of each solutions.
1.25 M CuBr2
how many grams of each ion would be present in 100mL of each solutions.
Answers
DrBob222
M CuBr2 = 1.25.
There is 1 Cu atom in 1 molecule CuBr2; therefore, M Cu^2+ ion is 1.25.
There are 2 Br atoms in 1 molecule CuBr2; therefore, M Br^- = 2*1.25 = ?
mols ion = M x L = ?
Convert to g; g = mols x ionic mass
There is 1 Cu atom in 1 molecule CuBr2; therefore, M Cu^2+ ion is 1.25.
There are 2 Br atoms in 1 molecule CuBr2; therefore, M Br^- = 2*1.25 = ?
mols ion = M x L = ?
Convert to g; g = mols x ionic mass