Asked by Terry
A box is to be formed from a rectangular piece of sheet metal by cutting squares measuring 5 inches on a side and then folding the sides. The piece of sheet metal is twice as long as it is wide. If the volume of the box is to be 1760 in^3, what are the dimensions of the original piece of sheet metal?
Answers
Answered by
Damon
height = 5
(L-10)(w-10)5 = 1760
(L-10)(w-10) = 352
L = 2 w
(2w-10)(w-10) = 352
(w-5)(w-10) = 176
w^2 - 15 w + 50 = 176
w^2 - 15 w - 126 = 0
(w-21)(w+6) = 0
so
w = 21
L = 42
(L-10)(w-10)5 = 1760
(L-10)(w-10) = 352
L = 2 w
(2w-10)(w-10) = 352
(w-5)(w-10) = 176
w^2 - 15 w + 50 = 176
w^2 - 15 w - 126 = 0
(w-21)(w+6) = 0
so
w = 21
L = 42
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