Using the balanced equation, 2 C2H2(g)+5 O2(g) yields 4 CO2(g)+2 H2O(g), at STP if 1mol of C2H2 burned in unlimited oxygen and the theoretical yield of carbon dioxide in liters at STP is 44.8 liters of carbon dioxide, and if 28.5 liters of carbon dioxide is produce to give you 63.62% yield, what is the actual yield?

asked by Lexia

10 years ago

1,391 views

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1 answer

The actual yield is 28.5 L according to the problem.
Try it. Isn't
(28.5/44.8)*100 = 63.62%? Sure is.

answered by DrBob222

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Question

Using the balanced equation, 2 C2H2(g)+5 O2(g) yields 4 CO2(g)+2 H2O(g), at STP if 1mol of C2H2 burned in unlimited oxygen and the theoretical yield of carbon dioxide in liters at STP is 44.8 liters of carbon dioxide, and if 28.5 liters of carbon dioxide is produce to give you 63.62% yield, what is the actual yield?

1 answer

The actual yield is 28.5 L according to the problem.
Try it. Isn't
(28.5/44.8)*100 = 63.62%? Sure is.

DrBob222 · Answer

The actual yield is 28.5 L according to the problem. Try it. Isn't (28.5/44.8)*100 = 63.62%? Sure is.