Asked by Tony

What mass of calcium bromide is needed to prepare 150.0 mL of a 3.50 M solution? (Assume that the molecular weight of CaBr2 is 200.618 g/mol)
A. 105 g
B. 100.42 g
C. 0.105 g
D. 103.35 g
Answered by DrBob222
See your MgSO4 problem below. Same process.
Answered by a
ferwrt5y6yu
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