Asked by sowmya
The numerator of a fraction is 4 less than twice the denominator. If both the numerator and the denominator are increased by 1, the fraction becomes 3/2. What is the original fraction?
Answers
Answered by
Steve
n = 2d-4
(n+1)/(d+1) = 3/2
(2d-4+1)/(d+1) = 3/2
2(2d-3) = 3(d+1)
4d-6 = 3d+3
d = 9
So, the original fraction is 14/9
(n+1)/(d+1) = 3/2
(2d-4+1)/(d+1) = 3/2
2(2d-3) = 3(d+1)
4d-6 = 3d+3
d = 9
So, the original fraction is 14/9
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