Asked by Todd

I don't completely understand what this question is asking:
Three people are standing on a horizontally rotating platform in an amusement park. One person is almost at the edge, the second one is (3/5)R from the center, and the third is (1/2)R from the center. Compare their periods of rotation, their speeds, and their radial accelerations.
I don't know how to find all that with the information given can someone explain what I'm suppose to do?

Answers

Answered by Steve
clearly, since they are all on the same rigid platform, their rotational periods are all the same.

Since the circumference is just a constant times the radius, their speeds are in the same proportion as their radii. Someone 1/2 as far out is going 1/2 as fast.

since the radial acceleration is v^2/r, someone twice as far out (2r) will have

a = (2v)^2/(2r) = 2(v^2/r)

or, twice the acceleration.
Answered by Anonymous
What are the #s for the problem .. like what is v what is r
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