Asked by leo
Under standard conditions for all concentrations, the following reaction is spontaneous at
25 ¢XC with EO = 0.16 V.
+ - 02 (g) + 4 H (aq) + 4 Br (aq) -+ 2 H20 (I) + 2 Br2 (1)
If [H+] is a?justed by adding a buffer of 0.10 M NaOCN and 0.10 M HOCN
(Ka = 3.5 x 10 ), what value will Ecell have, and will the reaction be spontaneous at this
[H+]?
25 ¢XC with EO = 0.16 V.
+ - 02 (g) + 4 H (aq) + 4 Br (aq) -+ 2 H20 (I) + 2 Br2 (1)
If [H+] is a?justed by adding a buffer of 0.10 M NaOCN and 0.10 M HOCN
(Ka = 3.5 x 10 ), what value will Ecell have, and will the reaction be spontaneous at this
[H+]?
Answers
Answered by
DrBob222
Leo, I can't decipher the symbols. BTW, did you omit the exponent on Ka = 3.5 x 10?
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