Asked by mathew
Calculate the acceleration of a sled that is heading down a 50° slope (one that makes an angle of 50° with the horizontal). The coefficient of kinetic friction on ice is
μk = 0.100.
(Take the x direction to be parallel to and down the slope and the y direction to be perpendicular to the slope.)
m/s2
Supporting Materials
μk = 0.100.
(Take the x direction to be parallel to and down the slope and the y direction to be perpendicular to the slope.)
m/s2
Supporting Materials
Answers
Answered by
Henry
Fp = Mg*sin50
Fn = Mg*Cos50
Fk = u*Fn = u*Mg*Cos50
Mg*sin50-0.1Mg*cos50 = M*a
Divide both sides by M:
g*sin50-0.1g*Cos50 = a
a = 9.8*sin50-0.98*Cos50 = 6.88 m/s^2.
Fn = Mg*Cos50
Fk = u*Fn = u*Mg*Cos50
Mg*sin50-0.1Mg*cos50 = M*a
Divide both sides by M:
g*sin50-0.1g*Cos50 = a
a = 9.8*sin50-0.98*Cos50 = 6.88 m/s^2.
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