Asked by Reina Bonilla
solve by using quadratic formula
x^2+2x-35=0
i got
x=10.85 or x=-12.85
x^2+2x-35=0
i got
x=10.85 or x=-12.85
Answers
Answered by
Reina Bonilla
x^2+10x+24=0
or
x^2-11x+24=0
or
x^2-11x+24=0
Answered by
Reina Bonilla
and*
Answered by
Steve
x^2+2x-35
x = (-2±√(4+140))/2
= (-2±12)/2
= 5,-7
Not sure how you got your answers, since you declined to show your work...
x^2+10x+24
(x+4)(x+6)
or, using the QF,
(-10±√4)/2
x^2-11x+24
(x-8)(x-3)
or, via QF,
(11±√25)/2
x = (-2±√(4+140))/2
= (-2±12)/2
= 5,-7
Not sure how you got your answers, since you declined to show your work...
x^2+10x+24
(x+4)(x+6)
or, using the QF,
(-10±√4)/2
x^2-11x+24
(x-8)(x-3)
or, via QF,
(11±√25)/2
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