n</= 2t+3 ???
is that not any n equal to or greater than -3
Find all values of t such that [t] =2t+3. If you find more than one value, then list the values you find in increasing order, separated by commas. The brackets represent the floor sign function.
5 answers
No it is equal
I can not.
⌊t⌋ = 2t+3
Clearly, t must be a multiple of 1/2
If an odd multiple, then we have
t = (2k+1)/2
⌊t⌋ = k
2t = 2k+1
k = 2k+1+3
k = -4
t = -7/2
If t is an even multiple of 1/2, then
⌊t⌋ = 2k/2 = k
2t = 2k
k = 2k+3
k = -3
t = -3
See the graphs at
http://www.wolframalpha.com/input/?i=%E2%8C%8At%E2%8C%8B+%3D+2t%2B3
Clearly, t must be a multiple of 1/2
If an odd multiple, then we have
t = (2k+1)/2
⌊t⌋ = k
2t = 2k+1
k = 2k+1+3
k = -4
t = -7/2
If t is an even multiple of 1/2, then
⌊t⌋ = 2k/2 = k
2t = 2k
k = 2k+3
k = -3
t = -3
See the graphs at
http://www.wolframalpha.com/input/?i=%E2%8C%8At%E2%8C%8B+%3D+2t%2B3
-7/2 and -3, in that respective order.