Question
The potential energy of a 2.0-kg particle moving along the x axis is given by
U(x) = 5.0 x^2.
When the particle is at x = 1.0 m it is traveling in the positive x direction with a speed of 1.5 m/s. It next stops momentarily to turn around at x =
U(x) = 5.0 x^2.
When the particle is at x = 1.0 m it is traveling in the positive x direction with a speed of 1.5 m/s. It next stops momentarily to turn around at x =