Connected in series means the resistances could be added.
Equivalent resistor = 4+10=14Ω
Voltage = 12 V
Assuming battery has zero internal resistance,
V=IR, or
I=V/R = 12/14 A = 6/7 A.
A 4 ohm resistor and 10 ohm resistor are connected in series. If this circuit is connected to a 12 V battery, how much current will flow through the circuit?
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