Asked by edi wow
a 150 gram bullet is fired with a speed of 50 ms if it is stopped after hitting a target 101 meters away what is its initial KE
Answers
Answered by
Damon
huh ?
(1/2) m v^2 = (1/2)(0.150)(2500) Joules
(1/2) m v^2 = (1/2)(0.150)(2500) Joules
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