Asked by Anonymous
A recent poll of a random sample of 400 students at a public 4-year college showed the average (mean) amount of time spent using email was 49 minutes per day with a standard deviation of 44 minutes.
a. find a 95% confidence interval fot the population mean
a. find a 95% confidence interval fot the population mean
Answers
Answered by
PsyDAG
It would help if you proofread your questions before you posted them. The information below only applies to a normal distribution. Your data do not indicate a normal distribution. Anything over 1.2 SD below the mean would be negative.
95% = mean ± 1.96 SEm
SEm = SD/√n
95% = mean ± 1.96 SEm
SEm = SD/√n
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.