Asked by Kyle
According to Newton's law of cooling, the rate at which an object cools is directly proportional to the difference in temperature between the object and the surrounding medium. The face of a household iron cools from 130° to 100° in 30 minutes in a room that remains at a constant temperature of 70°. From calculus, the temperature f(t) of the face after t hours of cooling is given by
f(x) = 60(2)^−2t + 70.
(a) Assuming t = 0 corresponds to 1:00 P.M., approximate to the nearest tenth of a degree the temperature of the face at 2:00 P.M., 3:30 P.M., and 4:00 P.M. (Round your answers to one decimal place.)
2:00 P.M. °
3:30 P.M. °
4:00 P.M. °
f(x) = 60(2)^−2t + 70.
(a) Assuming t = 0 corresponds to 1:00 P.M., approximate to the nearest tenth of a degree the temperature of the face at 2:00 P.M., 3:30 P.M., and 4:00 P.M. (Round your answers to one decimal place.)
2:00 P.M. °
3:30 P.M. °
4:00 P.M. °
Answers
Answered by
Damon
so just do it for t = 1 , 2.5 and 3
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