V^2 = Vo^2 + 2a*d
Vo = 0
a = F/m = 196.3/0.39 =
d = 1.28 m.
Solve for V.
An archer puts a 0.39 kg arrow to the bowstring.
An average force of 196.3 N is exerted
to draw the string back 1.28 m.
The acceleration of gravity is 9.8 m/s
2
.
Assuming no frictional loss, with what
speed does the arrow leave the bow?
Answer in units of m/s
1 answer
1 answer