Asked by Anonymous
A golf ball rolled off the edge of a table that has a height of 1.25 m and lands 0.48 m away from the table. The golf ball took 0.505 s to hit the ground 0.48 m from the table. What was the horizontal velocity, to the nearest hundredth m/s, of the ball as it rolled off the table?
Answers
Answered by
bobpursley
distance=velocity*time
.48m=v*.505s
solve for v
.48m=v*.505s
solve for v
Answered by
Anonymous
I have a follow-up question. So the horizontal velocity that we solved or, is that considered the initial or final velocity?
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