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Two cars,A and B, are traveling in the sam direction, although car A is 208m behind car B. The speed of A is 24.4 m/s, and the speed of B ia 18.6m/s. How much time does it take for A to catch B?

The answer is 208/5.8 which equals 35.8 seconds.

Since displacement is equal to change in velocity times time (d = v*t) -- rearranging the equation to solve for time you get time is equal to change in distance divided by change in velocity -- or t = 208/5.8

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