Asked by ulol
the perimeter of a rectangle is 56 m. the width of the rectangle is 4 m less than the length. find the length and width of the rectangle
Answers
Answered by
Bosnian
W = L - 4
P = 2 W + 2 L
P = 2 ( W + L )
P = 2 ( L - 4 + L )
P = 2 ( 2 L - 4 )
P = 2 * 2 L - 2 * 4
P = 4 L - 8
56 = 4 L - 8 Add 8 to both sides
56 + 8 = 4 L - 8 + 8
64 = 4 L Divide both sides by 4
64 / 4 = 4 L / 4
16 = L
L = 16 m
W = L - 4 = 16 - 4 = 12 m
Proof:
P = 2 ( W + L ) = 2 * ( 12 + 16 ) = 2 * 28 = 56 m
P = 2 W + 2 L
P = 2 ( W + L )
P = 2 ( L - 4 + L )
P = 2 ( 2 L - 4 )
P = 2 * 2 L - 2 * 4
P = 4 L - 8
56 = 4 L - 8 Add 8 to both sides
56 + 8 = 4 L - 8 + 8
64 = 4 L Divide both sides by 4
64 / 4 = 4 L / 4
16 = L
L = 16 m
W = L - 4 = 16 - 4 = 12 m
Proof:
P = 2 ( W + L ) = 2 * ( 12 + 16 ) = 2 * 28 = 56 m
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