Asked by Diolo
lim (e^x+3x)^1/x as x approaches 0
Answers
Answered by
Steve
I suspect a typo. Why the ^1 ?
At x=0, you have
(1+0)^1/0 = 1/0 = +∞
At x=0, you have
(1+0)^1/0 = 1/0 = +∞
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