first, the lifting force: 119N*sin30
now the normal force= mg-119*sin30
now the friction: mu* (mg-119Sin30)
pulling force: 119Cos30
net force=mass*acceleration
pullingforce-friction=mass(a)
solve for acceleration a.
Finally,
Vf^2=Vi^2+2ad solve for Vf
A 17.9 kg block is dragged over a rough, horizontal
surface by a constant force of 119 N
acting at an angle of 30◦
above the horizontal.
The block is displaced 40.7 m, and the
coefficient of kinetic friction is 0.111. what is the final speed
1 answer