Asked by Dave
Consider the 690 N weight held by two cables. The left-hand cable had tension T2 and makes an angle of 41◦ with the ceiling. The right-hand cable had tension T1 and makes an angle of 42◦ with the ceiling.
Answers
Answered by
bobpursley
first figure the angles the verticalmakes with the cables.
Left=49
right:48
Sum of vertical forces is zero.
690-L*cos49 -R*cos48=0
put that into the form
a*L + b*R=c
then second equation: sum horizontal forces is zero.
L*sin49-R*sin48=0
so you have two equations, two unknowns, solve for L, and R
Left=49
right:48
Sum of vertical forces is zero.
690-L*cos49 -R*cos48=0
put that into the form
a*L + b*R=c
then second equation: sum horizontal forces is zero.
L*sin49-R*sin48=0
so you have two equations, two unknowns, solve for L, and R
Answered by
Dave
Thanks!
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