Asked by Ciara
What is the value of A in the following nuclear reaction?
212/84Po→208/82Pb+A/ZX
212/84Po→208/82Pb+A/ZX
Answers
Answered by
bobpursley
Looks like z=2
looks like A= 212-208
X looks an alpha particle.
looks like A= 212-208
X looks an alpha particle.
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