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The sum of two numbers is 4 and the reciprocal of one exceeds the reciprocal of other by twice the product of their reciprocals. What is the product of the reciprocals of two numbers?

Please help me solving.

1 answer

M+N=4
1/M-1/N=2/MN

using the second equation, then
N-M=2

add that to the first equation
2N=6
N=3, M=1

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