Asked by Anonymous
1.) Find all solutions of the equation. Leave answers in trigonometric form.
x^2 + 1 - sqrt3i = 0
2.) Give the rectangular coordinates for the point.
(9, 2pi/3)
3.) The rectangular coordinates of a point are given. Express the point in polar coordinates with r L 0 and 0° K theta < 360°.
(1/4 , -sqrt3/4)
4.) For the given rectangular equation, give its equivalent polar equation.
8x - 7y = -10
I need help setting this up.
x^2 + 1 - sqrt3i = 0
2.) Give the rectangular coordinates for the point.
(9, 2pi/3)
3.) The rectangular coordinates of a point are given. Express the point in polar coordinates with r L 0 and 0° K theta < 360°.
(1/4 , -sqrt3/4)
4.) For the given rectangular equation, give its equivalent polar equation.
8x - 7y = -10
I need help setting this up.
Answers
Answered by
Steve
#1
in polar form,
-1+√3i = (2,2π/3)
So, the two square roots of that are
(√2,π/3) and (√2,4π/3)
#2,#3
just plug in
x = r cosθ
y = r sinθ
#4
8x - 7y = -10
7y - 8x = 10
7r sinθ - 8r cosθ = 10
r = 10/(7sinθ-8cosθ)
in polar form,
-1+√3i = (2,2π/3)
So, the two square roots of that are
(√2,π/3) and (√2,4π/3)
#2,#3
just plug in
x = r cosθ
y = r sinθ
#4
8x - 7y = -10
7y - 8x = 10
7r sinθ - 8r cosθ = 10
r = 10/(7sinθ-8cosθ)
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