Asked by Don
A spaceship is observed traveling in the positive x direction with a speed of 150m/s when it begins accelerating at a constant rate. The spaceship is observed 25s later traveling with an instantaneous velocity of 1500m/s at an angle of 55 degrees above the +x axis. What was the magnitude of the acceleration of the spaceship during the 25 seconds?
Answers
Answered by
Damon
new x velocity component = 1500 cos 55 = 860
change in x component = 860 - 150 = 710
change in y component = 1500 sin 55 = 1228
magnitude of change = sqrt(710^2+1228^2)
= 1419
1419/25 = 56.7 m/s^2
change in x component = 860 - 150 = 710
change in y component = 1500 sin 55 = 1228
magnitude of change = sqrt(710^2+1228^2)
= 1419
1419/25 = 56.7 m/s^2
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