Asked by Anonymous
Log(x-6) +Log(x+3)=1
Answers
Answered by
Reiny
I assume we are solving this equation ?
by rules of logs ....
log( (x-6)(x+3) ) = 1
10^1 = (x-6)(x+3)
x^2 - 3x - 18 = 10
x^2 - 3x - 28 = 0
(x-7)(x+4) = 0
x = 7 or x = -4 , but to be defined in log(x-6), x > 6
so x = 7
by rules of logs ....
log( (x-6)(x+3) ) = 1
10^1 = (x-6)(x+3)
x^2 - 3x - 18 = 10
x^2 - 3x - 28 = 0
(x-7)(x+4) = 0
x = 7 or x = -4 , but to be defined in log(x-6), x > 6
so x = 7
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.