Question

Acetylene gas(c2h2) is used in welding. During one job a welder burns 48.0 g of acetylene. Using a balanced equation for the complete combustion of acetylene calculate the following.
Equation 2C2H2 + 5O2 ---> 4CO2 + 2H2O
A) the mass of oxygen used
B) the mass of carbon dioxide produced
C) the mass of water produced

My answers
A) 73.7 g
B) 162.2 g
C) 14.8 g are these corect

Answer 1

B is right; A and C are not. If you will post your work I will find the error and correct.

Answer 2

A) mass of O2 = (48.0 C2H2/26.04 g/mol)(5O2/2C2H2)(16.00 g/mol) = 73.7 g of oxygen

C) mass of H2O = (48.0 g C2H2/26.04 g/mol)(2H2O/2C2H2)(18.02 g/mol) = 14.8 g of water

Answer 3

Thank you for posting your work. It makes it so much easier to catch the error and it let's me know about basic problems you may have.
For A you have done everything exactly right except the last step. The molar mass of oxygen is 32 since it is O2 and not O and the correct answer is just twice what you have.
For C you're set up is ok. You must have punched a wrong buttons on your calculator.
(48.0/26.04) x (2/2) x (18.02 = about 33.

Answer 4

So A would be 147.5 and C) 33.22

Answer 5

I also have another chemistry question that i am stuck on.

Answer 6

a and c are right now but on c you have an answer to too many significant figures. The 48.0 limits the answer to 3 s.f. so you should round that 33.22 to 33.2 grams for mass H2O.