Asked by kakak
how long is the groove on one side of a long play(33 1/3 rpm) phonograph record? assume there is a single recording and the author (beginning) groove is 5.75 inches from the center and the inner(ending) groove is 1.75 inches from the center. the recording plays for 23 minutes.
Answers
Answered by
Steve
23 min * 100/3 rev/min = 766.666 rev
So, divide the distance between the 1st and last grooves into 767 grooves, and you get
4/766.666 = 0.0052 inches between grooves
So, you have an arithmetic sequence with
a = 5.75*2π
d = 0.0052*2π
and you want S<sub>767</sub>
Just plug and chug
So, divide the distance between the 1st and last grooves into 767 grooves, and you get
4/766.666 = 0.0052 inches between grooves
So, you have an arithmetic sequence with
a = 5.75*2π
d = 0.0052*2π
and you want S<sub>767</sub>
Just plug and chug
Answered by
Gary
You would have to use 1.75*2pi for a or -0.0052 for d