Asked by kakak
                how long is the groove on one side of a long play(33 1/3 rpm) phonograph record? assume there is a single recording and the author (beginning) groove is 5.75 inches from the center and the inner(ending) groove is 1.75 inches from the center. the recording plays for 23 minutes.
            
            
        Answers
                    Answered by
            Steve
            
    23 min * 100/3 rev/min = 766.666 rev
So, divide the distance between the 1st and last grooves into 767 grooves, and you get
4/766.666 = 0.0052 inches between grooves
So, you have an arithmetic sequence with
a = 5.75*2π
d = 0.0052*2π
and you want S<sub>767</sub>
Just plug and chug
    
So, divide the distance between the 1st and last grooves into 767 grooves, and you get
4/766.666 = 0.0052 inches between grooves
So, you have an arithmetic sequence with
a = 5.75*2π
d = 0.0052*2π
and you want S<sub>767</sub>
Just plug and chug
                    Answered by
            Gary
            
    You would have to use 1.75*2pi for a or -0.0052 for d
    
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