F1 = 400N[32o]
F2 = 536N.[10o]
a. X = 400*Cos32 + 536*Cos10 =
Y = 400*sin32 + 536*sin10 =
Tan A = Y/X
A =
Fr = X/Cos A = Resultant force @ Ao.
b. a = Fr/m = Acceleration @ A Degrees.
Two forces are applied to a car in an effort to accelerate it, as shown below. The first force, F1 = 400 N, is applied at an angle α = 32° to the forward dashed line. The second force, F2 = 536 N, is applied at an angle β = 10° to the forward dashed line.
(a) What is the resultant of these two forces?
N at ° to the
of the forward dashed line
(b) If the car has a mass of 2900 kg, what acceleration does it have? (Disregard friction.)
m/s2 at ° to the
of the forward dashed line
1 answer