Asked by nikie
A girl coasts down a hill on a sled, reaching the bottom with a speed of 8.6 m/s. The coefficient of friction between the sled's runners and the snow is 0.050, and the girl and sled together weigh 670 N. How far does the sled travel on the surface before coming to rest?
Answers
Answered by
Henry
V^2 = Vo^2 + 2a*d
V = 0
Vo = 8.6 m/s.
a = u*g = 0.050*(-9.8) = -0.49 m/s^2
Solve for d.
V = 0
Vo = 8.6 m/s.
a = u*g = 0.050*(-9.8) = -0.49 m/s^2
Solve for d.