Asked by Nurul
                An n-sided polygon has interior angles of which 4 of them are of sizes 125,220,40 and 295 degrees . The remaining interior angles are of sizes 20 degrees each. Find the value of n,
My working:
let the number of sides for the polygon be n and the remaining number of sides be x.
(n-2)x 180 = 125+220+40+295+20x
180n-360=680+20x
180n=680+20x+360
180n=1040+20x
            
        My working:
let the number of sides for the polygon be n and the remaining number of sides be x.
(n-2)x 180 = 125+220+40+295+20x
180n-360=680+20x
180n=680+20x+360
180n=1040+20x
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